Modeling the 21-point plane
with outer automorphisms of 
S6
by Steven H. Cullinane
The following is adapted from a research note 
sent to various mathematicians on December 4, 1986. 
The symmetric group Sn has no outer automorphisms unless n = 6. 
The exceptional behavior of S6 may be studied via the internal 
geometry of each of this group's 720 = 6! outer automorphisms. In particular, 
each such automorphism t yields a model of the projective plane PG(2,4) in which 
the 21 2-sets and 1-sets in a 6-set S play double roles -- as points, and as 
lines. 
This note merely gives a recipe for such models, without proof that the 
recipe works. Some evidence, however, is given in an example. 
A model of PG(2,4) is specified by giving the 21 points and the 21 lines, and 
giving a rule that yields the 5 points on each line (or, dually, the 5 lines 
through each point). Our specifications will describe, given the automorphism t, 
how to build a 7-row by 21-column table T for a PG(2,4). Row 1 will be a list of 
lines, row 2 a list of points. The last 5 entries in each column will give the 5 
points on the line heading that column, and at the same time give the 5 lines 
through the point in entry 2 of that column. Each entry in T will be a 2-subset 
or 1-subset of S, pictured as 2 asterisks, or 1, in a 3x2 box. 
An automorphism of Sn is determined by its effect on 2-cycles, and 
the outer automorphisms of S6 take each 2-cycle to a product of 3 
disjoint 2-cycles. Our basic trick will be to regard 2-cycles as 2-sets, and 
products of 3 disjoint 2-cycles as partitions of S into 3 disjoint 2-sets. 
The following discussion refers to sections of T shown in figures 1 and 2 
below. 
Let t map the 15 2-cycles Li to the 15 involutions Bi 
that are products of 3 disjoint 2-cycles. Fill in the table-sections L and B 
accordingly. Let section Ai contain the two 1-subsets of S that 
appear in the 2-cycle (or 2-set) Li. Let section P' contain the six 
1-subsets of S. Let section Cj contain the six 2-subsets of S that 
each contain the 1-set P'j. 
If the table thus far can be completed to a PG(2,4) -- which has not 
been proved, since this recipe says "how," not "why" -- it is clear that there 
will be only one way to fill out the remaining sections, P and L' (in that 
order). 
For evidence that the recipe does work, see figure 3 below. 
Note that in all tables T constructed by this method, only sections P, L', 
and B vary from table to table, depending on the automorphism t that is used. 
Note also that if t is of order 2, lines and points become indistinguishable, 
and only one row (not two) of headings is needed. 
  FIGURE 1 
Sections of the PG(2,4) table in figure 
  3
  
  
    | L (lines)  | 
    L'  | 
  
    | P (points) | 
    P'  | 
  
    | A  | 
    C  | 
  
    | B  | 
  FIGURE 2
Subsections of the PG(2,4)in figure 3. The 
  shaded areas remain constant regardless of which automorphism of S6 
  is used to build the table. 
  
  
    | L1 | 
       | 
       | 
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       | 
    L15 | 
    L1' | 
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       | 
    L6' | 
  
    | P1 | 
       | 
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    P15 | 
    P1' | 
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    P6' | 
  
    | A1 | 
       | 
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    A15 | 
    C1 | 
       | 
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    C6 | 
  
    | B1 | 
       | 
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       | 
    B15 | 
  FIGURE 3
A model of PG(2,4) related to the Mathieu 
  group M24. 
  
  
    
      
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Page last modified February 5, 2001. 
Page created January 24, 2001.